Optimal. Leaf size=270 \[ \frac{2 \left (7 a^2-9 b^2\right ) \sqrt{a+b \tan (c+d x)}}{21 d \tan ^{\frac{3}{2}}(c+d x)}+\frac{2 b \left (49 a^2-3 b^2\right ) \sqrt{a+b \tan (c+d x)}}{21 a d \sqrt{\tan (c+d x)}}-\frac{2 a^2 \sqrt{a+b \tan (c+d x)}}{7 d \tan ^{\frac{7}{2}}(c+d x)}+\frac{i (-b+i a)^{5/2} \tan ^{-1}\left (\frac{\sqrt{-b+i a} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{d}-\frac{6 a b \sqrt{a+b \tan (c+d x)}}{7 d \tan ^{\frac{5}{2}}(c+d x)}+\frac{i (b+i a)^{5/2} \tanh ^{-1}\left (\frac{\sqrt{b+i a} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{d} \]
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Rubi [A] time = 1.29381, antiderivative size = 270, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 7, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.28, Rules used = {3565, 3649, 3616, 3615, 93, 203, 206} \[ \frac{2 \left (7 a^2-9 b^2\right ) \sqrt{a+b \tan (c+d x)}}{21 d \tan ^{\frac{3}{2}}(c+d x)}+\frac{2 b \left (49 a^2-3 b^2\right ) \sqrt{a+b \tan (c+d x)}}{21 a d \sqrt{\tan (c+d x)}}-\frac{2 a^2 \sqrt{a+b \tan (c+d x)}}{7 d \tan ^{\frac{7}{2}}(c+d x)}+\frac{i (-b+i a)^{5/2} \tan ^{-1}\left (\frac{\sqrt{-b+i a} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{d}-\frac{6 a b \sqrt{a+b \tan (c+d x)}}{7 d \tan ^{\frac{5}{2}}(c+d x)}+\frac{i (b+i a)^{5/2} \tanh ^{-1}\left (\frac{\sqrt{b+i a} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{d} \]
Antiderivative was successfully verified.
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Rule 3565
Rule 3649
Rule 3616
Rule 3615
Rule 93
Rule 203
Rule 206
Rubi steps
\begin{align*} \int \frac{(a+b \tan (c+d x))^{5/2}}{\tan ^{\frac{9}{2}}(c+d x)} \, dx &=-\frac{2 a^2 \sqrt{a+b \tan (c+d x)}}{7 d \tan ^{\frac{7}{2}}(c+d x)}+\frac{2}{7} \int \frac{\frac{15 a^2 b}{2}-\frac{7}{2} a \left (a^2-3 b^2\right ) \tan (c+d x)-\frac{1}{2} b \left (6 a^2-7 b^2\right ) \tan ^2(c+d x)}{\tan ^{\frac{7}{2}}(c+d x) \sqrt{a+b \tan (c+d x)}} \, dx\\ &=-\frac{2 a^2 \sqrt{a+b \tan (c+d x)}}{7 d \tan ^{\frac{7}{2}}(c+d x)}-\frac{6 a b \sqrt{a+b \tan (c+d x)}}{7 d \tan ^{\frac{5}{2}}(c+d x)}-\frac{4 \int \frac{\frac{5}{4} a^2 \left (7 a^2-9 b^2\right )+\frac{35}{4} a b \left (3 a^2-b^2\right ) \tan (c+d x)+15 a^2 b^2 \tan ^2(c+d x)}{\tan ^{\frac{5}{2}}(c+d x) \sqrt{a+b \tan (c+d x)}} \, dx}{35 a}\\ &=-\frac{2 a^2 \sqrt{a+b \tan (c+d x)}}{7 d \tan ^{\frac{7}{2}}(c+d x)}-\frac{6 a b \sqrt{a+b \tan (c+d x)}}{7 d \tan ^{\frac{5}{2}}(c+d x)}+\frac{2 \left (7 a^2-9 b^2\right ) \sqrt{a+b \tan (c+d x)}}{21 d \tan ^{\frac{3}{2}}(c+d x)}+\frac{8 \int \frac{-\frac{5}{8} a^2 b \left (49 a^2-3 b^2\right )+\frac{105}{8} a^3 \left (a^2-3 b^2\right ) \tan (c+d x)+\frac{5}{4} a^2 b \left (7 a^2-9 b^2\right ) \tan ^2(c+d x)}{\tan ^{\frac{3}{2}}(c+d x) \sqrt{a+b \tan (c+d x)}} \, dx}{105 a^2}\\ &=-\frac{2 a^2 \sqrt{a+b \tan (c+d x)}}{7 d \tan ^{\frac{7}{2}}(c+d x)}-\frac{6 a b \sqrt{a+b \tan (c+d x)}}{7 d \tan ^{\frac{5}{2}}(c+d x)}+\frac{2 \left (7 a^2-9 b^2\right ) \sqrt{a+b \tan (c+d x)}}{21 d \tan ^{\frac{3}{2}}(c+d x)}+\frac{2 b \left (49 a^2-3 b^2\right ) \sqrt{a+b \tan (c+d x)}}{21 a d \sqrt{\tan (c+d x)}}-\frac{16 \int \frac{-\frac{105}{16} a^4 \left (a^2-3 b^2\right )-\frac{105}{16} a^3 b \left (3 a^2-b^2\right ) \tan (c+d x)}{\sqrt{\tan (c+d x)} \sqrt{a+b \tan (c+d x)}} \, dx}{105 a^3}\\ &=-\frac{2 a^2 \sqrt{a+b \tan (c+d x)}}{7 d \tan ^{\frac{7}{2}}(c+d x)}-\frac{6 a b \sqrt{a+b \tan (c+d x)}}{7 d \tan ^{\frac{5}{2}}(c+d x)}+\frac{2 \left (7 a^2-9 b^2\right ) \sqrt{a+b \tan (c+d x)}}{21 d \tan ^{\frac{3}{2}}(c+d x)}+\frac{2 b \left (49 a^2-3 b^2\right ) \sqrt{a+b \tan (c+d x)}}{21 a d \sqrt{\tan (c+d x)}}+\frac{1}{2} (a-i b)^3 \int \frac{1+i \tan (c+d x)}{\sqrt{\tan (c+d x)} \sqrt{a+b \tan (c+d x)}} \, dx+\frac{1}{2} (a+i b)^3 \int \frac{1-i \tan (c+d x)}{\sqrt{\tan (c+d x)} \sqrt{a+b \tan (c+d x)}} \, dx\\ &=-\frac{2 a^2 \sqrt{a+b \tan (c+d x)}}{7 d \tan ^{\frac{7}{2}}(c+d x)}-\frac{6 a b \sqrt{a+b \tan (c+d x)}}{7 d \tan ^{\frac{5}{2}}(c+d x)}+\frac{2 \left (7 a^2-9 b^2\right ) \sqrt{a+b \tan (c+d x)}}{21 d \tan ^{\frac{3}{2}}(c+d x)}+\frac{2 b \left (49 a^2-3 b^2\right ) \sqrt{a+b \tan (c+d x)}}{21 a d \sqrt{\tan (c+d x)}}+\frac{(a-i b)^3 \operatorname{Subst}\left (\int \frac{1}{(1-i x) \sqrt{x} \sqrt{a+b x}} \, dx,x,\tan (c+d x)\right )}{2 d}+\frac{(a+i b)^3 \operatorname{Subst}\left (\int \frac{1}{(1+i x) \sqrt{x} \sqrt{a+b x}} \, dx,x,\tan (c+d x)\right )}{2 d}\\ &=-\frac{2 a^2 \sqrt{a+b \tan (c+d x)}}{7 d \tan ^{\frac{7}{2}}(c+d x)}-\frac{6 a b \sqrt{a+b \tan (c+d x)}}{7 d \tan ^{\frac{5}{2}}(c+d x)}+\frac{2 \left (7 a^2-9 b^2\right ) \sqrt{a+b \tan (c+d x)}}{21 d \tan ^{\frac{3}{2}}(c+d x)}+\frac{2 b \left (49 a^2-3 b^2\right ) \sqrt{a+b \tan (c+d x)}}{21 a d \sqrt{\tan (c+d x)}}+\frac{(a-i b)^3 \operatorname{Subst}\left (\int \frac{1}{1-(i a+b) x^2} \, dx,x,\frac{\sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{d}+\frac{(a+i b)^3 \operatorname{Subst}\left (\int \frac{1}{1-(-i a+b) x^2} \, dx,x,\frac{\sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{d}\\ &=\frac{i (i a-b)^{5/2} \tan ^{-1}\left (\frac{\sqrt{i a-b} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{d}+\frac{i (i a+b)^{5/2} \tanh ^{-1}\left (\frac{\sqrt{i a+b} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{d}-\frac{2 a^2 \sqrt{a+b \tan (c+d x)}}{7 d \tan ^{\frac{7}{2}}(c+d x)}-\frac{6 a b \sqrt{a+b \tan (c+d x)}}{7 d \tan ^{\frac{5}{2}}(c+d x)}+\frac{2 \left (7 a^2-9 b^2\right ) \sqrt{a+b \tan (c+d x)}}{21 d \tan ^{\frac{3}{2}}(c+d x)}+\frac{2 b \left (49 a^2-3 b^2\right ) \sqrt{a+b \tan (c+d x)}}{21 a d \sqrt{\tan (c+d x)}}\\ \end{align*}
Mathematica [A] time = 3.49008, size = 249, normalized size = 0.92 \[ -\frac{\frac{\sec ^3(c+d x) \sqrt{a+b \tan (c+d x)} \left (a \left (2 a^2+9 b^2\right ) \cos (c+d x)+\left (10 a^3-9 a b^2\right ) \cos (3 (c+d x))+2 b \sin (c+d x) \left (\left (58 a^2-3 b^2\right ) \cos (2 (c+d x))-40 a^2+3 b^2\right )\right )}{a \tan ^{\frac{7}{2}}(c+d x)}-42 (-1)^{3/4} (-a-i b)^{5/2} \tanh ^{-1}\left (\frac{\sqrt [4]{-1} \sqrt{-a-i b} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )+42 (-1)^{3/4} (a-i b)^{5/2} \tanh ^{-1}\left (\frac{\sqrt [4]{-1} \sqrt{a-i b} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{42 d} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.341, size = 1310269, normalized size = 4852.9 \begin{align*} \text{output too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b \tan \left (d x + c\right ) + a\right )}^{\frac{5}{2}}}{\tan \left (d x + c\right )^{\frac{9}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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